im having trouble Implementing the function min that takes three numbers and return smallest, help!?

You have the Math builtin object that would do the trick here quite quickly.

@tevinchy write down all the possible scenarios. Then come up with if statements for each of them. @kerstman Math.min is an overkill for this task

Coderslang_Master Thanks, it required a bit of basic mathematics to get around

I'm also struggling to get this one to pass. my solution: export const min = (a, b, c) => { if (a < b && c) { return a; } if (b < a && c) { return b; } if (c < a && b) { return c; } }; It physically seems to work when I run it, but I get to following 2 errors when I run tests: The min function should return the minimum of 3 numbers. min should not return undefined. Any ideas?

Hacktinium what if a is equal to b and c ?

Coderslang_Master Gotchya 😉 1 is not less than 1, so it's going to return 'undefined'.

a part of my solution if (a < b) { if (c < a) { return c; } else { return a; } } else {bla bla bla}

Hacktinium exactly @bulentala you should make sure that the function always returns something, even if all the arguments are equal

I tried so hard and got so far But in the end it ....... export const min = (a, b, c) => { if (b>c && a>c) return (c); if (a>b && c>b) return (b); if (b>a && c>a) return (a); if (a+b===c b+c===a c+a===b) return (p); if (a===b) return (g); if (b===c) return (q); if (c===a) return (l); } still faced : the min function should return the min of 3 numbers min should not return undefined. Beggin for help

task 121

thaishps

I had problems too, but I passed the task. Here my solution.

export const min = (a, b, c) => {
if (a <= b && a <= c) {
return a;
} else {
if (a >= b && b <= c) {
return b;
} else {
return c;
}
}
};

Greeting from Venezuela 😄

maverick

Had issues, but here is my solution that worked.

export const min = (a, b, c) => {
if (a < b && a < c) {
return a;
} else if ( b < a && b < c) {
return b;
} else {
return c;
}
}

Lowrentpepe

My solution if I may 😁
export const min = (a, b, c) => {
if (a<b && a<c){
return (a);
} else
if (b<a && b<c){
return(b);
} else
if (c<a && c<b){
return(c);
} else
if (a===b && a===c && b==c){
return(a,b,c);
}
}

gloryarisah

How i passed it ->
export const min = (a, b, c) => {
if (a < b) {
if (a < c) {
return a;
} else {
return c;
}
}
if (b < a) {
if (b < c) {
return b;
} else {
return c
}
}
if (c < a) {
if (c < b) {
return c;
} else {
return b
}
}
if (a === b && a === c && b === c) {
return a;
}
}

techbantu

This is the smallest code i can write so far.

 {
if (a < b && a < c) return a;
  else if (b < a && b < c) return b;
  else return c;
}

alorenz

techbantu even shorter ;-)

{
if (a < b && c) return a;
else if (b < a && c) return b;
else return c;
}

@Coderslang_Master What I didn't understand is what is the $ sign good for in the solution.js file?

console.log(The minimum is ${min(a, b, c)});

And one more thing: With my proposed solution described above, I get the right outcome every time I run the code, but when I submit it, the following step gets marked as incorrect. What's wrong?

The min function should return the minimum of 3 numbers

Andru

Esta es mi solución:
export const min = (a, b, c) => {
if (a < b && a < c) return a;
else if (b < c && b < a) return b;
else if (c < b && c < a) return c;
else return a or b or c;
}

}

hugolee0003

Well i struggled with it at first but here's my solution 😊
export const min = (a, b, c) => { if((a < b) && (a < c)){ return a; } else if((b < a) && (b < c)){ return b; } else{ return c; } }

Coderslang_Master

alorenz it's the template string, you'll learn it in the future lectures.

Speaking of the issue with your code, you'll find it if you test with more values. At the very least you should consider the situation when a = b or b = c.

alorenz

Coderslang_Master didn't see that coming.... but at the end of the day, I'm happy it was more of a math issue than a coding one! 😅

Coderslang_Master

alorenz on the same notion counting the change in the supermarket is math too 🙂

alorenz

Coderslang_Master don't get me wrong, nothing against math. it's just that i was fully focused on a possible coding structure error and didn't see that it had more to do with an error with the mathematical logic

Coderslang_Master

alorenz an error can come from the most unexpected direction 🙂

Sylva55

Hello everyone, I hope there’s still time to help.
here’s my code :

function findMin(a, b){
    if(a < b){
        return a;
}
return b;
}
console.log(findMin(10, 2));

function min3(a,b,c){
    return findMin(findMin(a,b),c);
}

console.log(min3(10,4,3));

I tested it. It works

Coderslang_Master

Sylva55 looks good, could you add the submission results?

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