task 121

tevinchy

im having trouble Implementing the function min that takes three numbers and return smallest, help!?

raka29

same here i need help

kerstman

You have the Math builtin object that would do the trick here quite quickly.

Coderslang_Master

@tevinchy write down all the possible scenarios. Then come up with if statements for each of them.

@kerstman Math.min is an overkill for this task

tevinchy

Coderslang_Master Thanks, it required a bit of basic mathematics to get around

Hacktinium

I'm also struggling to get this one to pass.
my solution:

export const min = (a, b, c) => {
	if (a < b && c) {
		return a;
	}
	if (b < a && c) {
		return b;
	}
	if (c < a && b) {
		return c;
	}
};

It physically seems to work when I run it, but I get to following 2 errors when I run tests:

The min function should return the minimum of 3 numbers.
min should not return undefined.

Any ideas?

Coderslang_Master

Hacktinium what if a is equal to b and c?

Hacktinium

Coderslang_Master

Gotchya 😉 1 is not less than 1, so it's going to return 'undefined'.

Coderslang_Master

Hacktinium exactly

@bulentala you should make sure that the function always returns something, even if all the arguments are equal

bulentala

a part of my solution

if (a < b) {
if (c < a) {
return c;
} else {
return a;
}
} else {bla bla bla}

Evgeny

I tried so hard and got so far
But in the end it .......

export const min = (a, b, c) => {
if (b>c && a>c)
return (c);
if (a>b && c>b)
return (b);
if (b>a && c>a)
return (a);
if (a+b===c b+c===a c+a===b)
return (p);
if (a===b)
return (g);
if (b===c)
return (q);
if (c===a)
return (l);
}

still faced :
the min function should return the min of 3 numbers
min should not return undefined.

Beggin for help

Evgeny

Evgeny
UPD: Solved
It was needed to use "else"

Coderslang_Master

Evgeny you can also make your code shorter by using "less than or equal" operator - <=

thaishps

I had problems too, but I passed the task. Here my solution.

export const min = (a, b, c) => {
if (a <= b && a <= c) {
return a;
} else {
if (a >= b && b <= c) {
return b;
} else {
return c;
}
}
};

Greeting from Venezuela 😄

maverick

Had issues, but here is my solution that worked.

export const min = (a, b, c) => {
if (a < b && a < c) {
return a;
} else if ( b < a && b < c) {
return b;
} else {
return c;
}
}

Lowrentpepe

My solution if I may 😁
export const min = (a, b, c) => {
if (a<b && a<c){
return (a);
} else
if (b<a && b<c){
return(b);
} else
if (c<a && c<b){
return(c);
} else
if (a===b && a===c && b==c){
return(a,b,c);
}
}

gloryarisah

How i passed it ->
export const min = (a, b, c) => {
if (a < b) {
if (a < c) {
return a;
} else {
return c;
}
}
if (b < a) {
if (b < c) {
return b;
} else {
return c
}
}
if (c < a) {
if (c < b) {
return c;
} else {
return b
}
}
if (a === b && a === c && b === c) {
return a;
}
}

techbantu

This is the smallest code i can write so far.

 {
if (a < b && a < c) return a;
  else if (b < a && b < c) return b;
  else return c;
}

alorenz

techbantu even shorter ;-)

{
if (a < b && c) return a;
else if (b < a && c) return b;
else return c;
}

@Coderslang_Master What I didn't understand is what is the $ sign good for in the solution.js file?

console.log(The minimum is ${min(a, b, c)});

And one more thing: With my proposed solution described above, I get the right outcome every time I run the code, but when I submit it, the following step gets marked as incorrect. What's wrong?

The min function should return the minimum of 3 numbers

Andru

Esta es mi solución:
export const min = (a, b, c) => {
if (a < b && a < c) return a;
else if (b < c && b < a) return b;
else if (c < b && c < a) return c;
else return a or b or c;
}

}

hugolee0003

Well i struggled with it at first but here's my solution 😊
export const min = (a, b, c) => { if((a < b) && (a < c)){ return a; } else if((b < a) && (b < c)){ return b; } else{ return c; } }